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yes, but compiler can handle it diffrend way than creating a pointer by using *. if you thing that way, then everything is pointer to some location in memory (yes, data must be stored somewhere) int is array of 4 chars: int somenum; char somechars[4]; char is pointer without using *? and why int isn...

i still dont understand why: savedata->saveNameMultiple = (char **) nameMultiple; and no: savedata->saveNameMultiple = &nameMultiple; (it is just pointer = pointer) (becouse & makes pointer from non pointer) becouse there are two '**' markers, every marker means pointer, so it is pointer to ...

great, now i understant it more, but if i create: char *names[6] = { "NAME1", "NAME2", "NAME3", "NAME4", "NAME5", "" // Terminator }; then its size is 6*4 bytes, and every 4 bytes is pointer to char(s). For...

but if i define pointer to something, an non pointer, then i must use & character ... char *point; // 4 bytes char nonpoint // 1 byte i can do: nonpoint = 'X'; but i cant do: point = 'X'; // becouse pointer is not set, and it will try to write to address 0x00000000 i can use: point = malloc(1); ...

but, in first post is this: in struct SceUtilitySavedataParam: char *saveNames; pointer to char(s), is it right? and after i defined new struct typedef struct { char name1[20]; char name2[20]; char name3[20]; char name4[20]; char name5[20]; char nothing[20]; // Terminator } savenames_t; no pointers,...

i am not sure about this line: char **saveNameMultiple; it is pointer to pointer to char(s), but what i use is just: char *saveNameMultiple; pointer to char(s) and with this: savedata->saveNameMultiple = (char **) nameMultiple; isnt better to do savedata->saveNameMultiple = &nameMultiple; of cou...

I dont know if it is somewhere on net ... I wanted to update all 3 ports (hexen, heretic, doom) with PSP's system functions, and i discovered bug in SceUtilitySavedataParam, i found correct things in memory of original game, there is fix: typedef struct SceUtilitySavedataParam { pspUtilityD...